August 21, 200422 yr x = y x2 = xy x2 - y2 = xy - y2 (x + y)(x - y) = y(x - y) x + y = y so, 1 + 1 = 1, or 2 = 1 Ain't math grand?
August 21, 200422 yr Sorry, I had to do this, the flaw starts in the fourth line. Yes it is true that (x+y)(x-y)=y(x-y). But, since x=y, x-y=0. Therefore, the zero property of multiplication comes into play: any number times zero equals zero. So, you cant say that x+y=y. Thats like saying 100 times 0 equals 0, and 50 times 0 equals 0, therefore 50 and 100 are equal.
August 21, 200422 yr Sorry, I had to do this, the flaw starts in the fourth line. Yes it is true that (x+y)(x-y)=y(x-y). But, since x=y, x-y=0. Therefore, the zero property of multiplication comes into play: any number times zero equals zero. So, you cant say that x+y=y. Thats like saying 100 times 0 equals 0, and 50 times 0 equals 0, therefore 50 and 100 are equal. 520294[/snapback] yeah my bro pointed that out to me also. :thumbup
August 21, 200422 yr Meh, Math is fun if you know what you're doing otherwise it's hell. When I have rational thinkin(word problems and equations). I usually can do well but once you get stuck up I despise the subject.
August 21, 200422 yr Author 3/3 = .9999999 520137[/snapback] .9999999 repeating is infamous for being exactly 1. :whistle
August 21, 200422 yr Sorry, I had to do this, the flaw starts in the fourth line. Yes it is true that (x+y)(x-y)=y(x-y). But, since x=y, x-y=0. Therefore, the zero property of multiplication comes into play: any number times zero equals zero. So, you cant say that x+y=y. Thats like saying 100 times 0 equals 0, and 50 times 0 equals 0, therefore 50 and 100 are equal. 520294[/snapback] Glad to see someone else saw this
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